Saturday, October 4, 2008

Arithmetic Series

Sum (the arithmetic series)

The sum of the components of an arithmetic progression is called an arithmetic series.

[edit] Formula (for the arithmetic series)

Express the arithmetic series in two different ways:

 S_n=a_1+(a_1+d)+(a_1+2d)+\dots\dots+(a_1+(n-2)d)+(a_1+(n-1)d)

 S_n=(a_n-(n-1)d)+(a_n-(n-2)d)+\dots\dots+(a_n-2d)+(a_n-d)+a_n.

Add both sides of the two equations. All terms involving d cancel, and so we're left with:

\ 2S_n=n(a_1+a_n).

Rearranging and remembering that an = a1 + (n − 1)d, we get:

 S_n=\frac{n( a_1 + a_n)}{2}=\frac{n[ 2a_1 + (n-1)d]}{2}.

[edit] Product

The product of the components of an arithmetic progression with an initial element a1, common difference d, and n elements in total, is determined in a closed expression by

a_1a_2\cdots a_n = d^n {\left(\frac{a_1}{d}\right)}^{\overline{n}} = d^n \frac{\Gamma \left(a_1/d + n\right) }{\Gamma \left( a_1 / d \right) },

where x^{\overline{n}}denotes the rising factorial and Γ denotes the Gamma function. (Note however that the formula is not valid when a1 / d is a negative integer or zero).

This is a generalization from the fact that the product of the progression 1 \times 2 \times \cdots \times nis given by the factorial n! and that the product

m \times (m+1) \times (m+2) \times \cdots \times (n-2) \times (n-1) \times n \,\!

for positive integers m and n is given by

\frac{n!}{(m-1)!}.

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